How many Morgan silver dollars make a pound? This is a question that often arises among collectors and investors who are interested in the value and weight of these historical coins. The answer to this question can vary depending on several factors, including the condition of the coins and the current market value of silver.
Morgan silver dollars, minted from 1878 to 1904 and again in 1921, are composed of 90% silver and 10% copper. Each coin weighs approximately 26.73 grams, which is equivalent to 0.8591 troy ounces. To determine how many Morgan silver dollars make a pound, we need to convert the weight of a pound (453.592 grams) into troy ounces and then divide that by the weight of a single Morgan silver dollar.
First, let’s convert the weight of a pound into troy ounces. Since there are 31.1034768 grams in a troy ounce, we can calculate the number of troy ounces in a pound by dividing 453.592 grams by 31.1034768 grams per troy ounce:
453.592 grams / 31.1034768 grams per troy ounce = 14.5835 troy ounces
Now that we have the number of troy ounces in a pound, we can divide that by the weight of a single Morgan silver dollar in troy ounces (0.8591 troy ounces) to find out how many coins make up a pound:
14.5835 troy ounces / 0.8591 troy ounces per coin = 16.9886 coins
Therefore, approximately 16.99 Morgan silver dollars make up a pound. It’s important to note that this calculation is based on the weight of the coins and does not take into account their current market value or condition. The actual value of a pound of Morgan silver dollars can vary significantly depending on the silver price and the collectibility of the coins.
For collectors and investors, knowing how many Morgan silver dollars make a pound can help in determining the quantity of coins needed to achieve a specific silver content or to compare the value of different collections. Additionally, understanding the weight and value of these coins can be beneficial when planning for investment or when dealing with the coins in a transaction.
